# If the median of

Given: The frequency table.
To find: The missing frequencies f1 and f2 .
Solution: Construct a table to calculate cumulative frequencies,

The table is shown below:

Given, Median = 28.5

As it lies in the interval 20-30,

So, median class is 20-30

Now,

l, lower class = 20,
frequency of median class, f = 20,
Cumulative frequency of class preceding the median class, F = 5 + f1,
height of class, h = 10
N is 60,

we know,

28.5 = 20 + * 10

28.5 – 20 = * 10

8.5 =
17 = 25 - f1

f1 = 25 – 17

f1 = 8

Given, sum of frequencies = 60

i.e.  5 + f1 + 20 + 15 + f2 + 5 = 60
Put the value of f1

therefore,  5 + 8 + 20 + 15 + f2 + 5 = 60

hence, f2 = 7

Therefore, f1 = 8 and f2 = 7

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