Q. 43.7( 87 Votes )

# Find the equivalent fraction of having:

(a) denominator 20

(b) numerator 9

(c) denominator 30

(d) numerator 9

Answer :

(a)

3× 20 = 5× ?

3 × 2 × 2 × 5 = 5 × ?

12 = ?

Hence,

The required fraction is

(b)

3× ? = 5× 9

5 × 3 × 3 = 3 × ?

15 = ?

Hence,

The required fraction is

(c)

3× 30 = 5× ?

3 × 2 × 3 × 5 = 5 × ?

18 = ?

Hence,

The required fraction is

(d)

3× ?= 5× 27

5 × 3 × 3 × 3= 3 × ?

45 = ?

Hence,

The required fraction is

Rate this question :

Look at the figures and write ‘<’, ‘=’ or ‘>’ between given pairs of fractions:

(a)

(b)

(c)

(d)

(e)

Make five more such problems and solve them your friends.

NCERT - MathematicsMake five more such pairs and put appropriate signs.

NCERT - MathematicsHow quickly can you do this? Fill appropriate sign (‘<’, ‘=’ or ‘>’):

(a) (b)

(c) (d)

(e) (f)

(g) (h)

(i) (j)

(k)

NCERT - MathematicsMatch the equivalent fractions and write two more for each.

(i) (a)

(ii) (b)

(iii) (c)

(iv) (d)

(v) (e)

NCERT - MathematicsFind the equivalent fraction of with:

(a) numerator 9

(b) Denominator 4

NCERT - MathematicsFind the equivalent fraction of having:

(a) denominator 20

(b) numerator 9

(c) denominator 30

(d) numerator 9

NCERT - MathematicsWrite the fractions. Are all these fractions equivalent?

(a)

(b)

NCERT - MathematicsCheck whether the given fractions are equivalent:

(a)

(b)

(c)

NCERT - Mathematics