Q. 15 A4.3( 3 Votes )

a2b2x2 + b2x – a2x — 1 = 0, a ≠ 0, b ≠ 0

Answer :

b2x {a2x + 1} – 1 {a2x + 1} = 0


(b2x – 1) (a2x + 1) = 0


b2x – 1 = 0 a2x + 1 = 0



Therefore, the roots of the equation are.


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