Q. 153.9( 62 Votes )
Find the integrals of the functions.
Answer :
tan32xsec2x = tan22xtan2xsec2x
= (sec22x -1)tan2xsec2x
= sec22x.tan2xsec2x-tan2xsec2x
⇒ 
⇒ 
Now, Let sec2x = t
⇒ 2sec2xtan2x dx = dt
Thus, 
⇒ 
⇒ 
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