Q. 153.8( 86 Votes )

Find the integral

Answer :

tan32xsec2x = tan22xtan2xsec2x

= (sec22x -1)tan2xsec2x


= sec22x.tan2xsec2x-tan2xsec2x




Now, Let sec2x = t


2sec2xtan2x dx = dt


Thus,




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