# CDE is an equilat

Given: CDE is an equilateral triangle formed on a side CD of a square ABCD.

DE = CE (sides of equilateral triangle)

Now, ADC = BCD = 90° and EDC = ECD = 60°

Hence, ADE = ADC + CDE = 90° + 60° = 150°

And BCE = BCD + ECD = 90° + 60° = 150°

AD = BC (sides of square)

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