Q. 213.7( 95 Votes )

Integrate the fun

Answer :

tan2 (2x – 3) = sec2 (2x – 3) – 1

Let 2x -3 = t


2dx = dt






⇒ 1/2 tan t - t + C

⇒ 1/2 tan (2x - 3) - (2x - 3) + C

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