Q. 154.8( 4 Votes )

The angles of ele

Answer :


Let C be position of station 1 and D of station 2 and BC = x.


Given, CD = 4000 km


Now, in triangle ABC,


ACB = 60°


We know,





AB = √3BC


AB = x√3 ……… (1)


And, in triangle ABD,


ADB = 30°


We know,






……… (2)


Now, equating (1) & (2), we get–



3 x = x + 4000


3x – x = 4000


2x = 4000


x = 2000


And distance between the satellite and earth(AB) = x√3


= 2000(1.732)


= 3464 km


Distance between the satellite and earth = 3464 km


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