# If sin 3θ = cos (

As we know,

cos θ = sin (90˚ – θ)

sin 3θ = cos (θ – 6˚)

sin 3θ = sin (90˚ – (θ – 6˚))

sin 3θ = sin (90˚ – θ + 6˚)

sin 3θ = sin (96˚ – θ)

Since, 3θ is acute angle

So, 3θ = 96˚ – θ

4θ = 96˚

θ = = 24˚

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