Answer :

Given, time taken by van to reach D from C = 6 minutes.

And let the speed = x

We know,

Distance = speed × time

⇒ Distance between D and C = DC = 6x

In triangle ACB,

∠ACB = ∠ OAC (alternate angles are equal)

= 30°

Also,

……… (1)

Now, in triangle ABD,

∠ABD = ∠ OAD (alternate angles are equal)

= 60°

We know,

AB = BD√3 ……… (2)

Now, equating (1) & (2), we get–

⇒ BD + 6x = BD × 3

⇒ 2BD = 6x

⇒ BD = 3x (where, x is speed)

Now, comparing it with Distance = speed × time, we have–

Time = 3 minutes.

Hence, it take 3 minutes more for the van to reach the tower.

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