Answer :
Let (3, 0), (4, 5), ( - 1, 4) and ( - 2, - 1) are the vertices A, B, C, D of a rhombus ABCD
Length of diagonal AC = [(3 + 1)2 + (0 – 4)2]1/2
= 
= 
Length of diagonal BD = [(4 + 2)2 + (5+ 1)2]1/2
= 
= 6
Therefore,
Area of rhombus = 1/2 (Product of the length of the diagonals)Therefore,
Area of rhombus ABCD = 1/2 × 
× 6
= 1/2 × 48
= 24 square units
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