Q. 95.0( 1 Vote )

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PQ + QR = 7

PR + QS = 10

Since Diagonals of a rectangle are of equal length, so

PR = QS = 5

Let PQ be x, QR = 7 – x

Applying Pythagoras theorem :

x2 + (7 – x)2 = 52

2x2 – 14x + 24 = 0

x2 – 7x + 12 = 0

x2 – 4x – 3x + 12 = 0

x(x – 4) – 3(x – 4) = 0

(x – 3)(x – 4) = 0

x = 3, 4

The two sides are 3 and 4

Area of the Rectangle = (3 × 4) = 12 sq. units

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