# If Q(0, 1) is equidistant from P(5, –3) and R(x, 6), find the values of x. Also find the distances QR and PR We know, By distance formula distance between two coordinates A(x1, y1) and B(x2, y2) is

AB = √[(x2 - x1)2 + (y2 - y1)2 ]

Now, as

PQ = QR

√[(5 - 0)2 + (- 3 - 1)2] = √[(0 - x)2 + (1 - 6)2] = x2 + 25

Squaring both sides,

41 = x2 + 25

x2 = 16

x = ± 4

Hence, point R is (4, 6) or ( - 4, 6).

When point R is (4, 6)

PR = [(5 - 4)2 + (-3 - 6)2]1/2

= = QR = [(0 - 4)2 + (1 - 6)2]1/2

= = When point R is (- 4, 6),

PR = [(5 + 4)2 + (-3 - 6)2]1/2

= = 9 QR = [(0+ 4)2 + (1 - 6)2]1/2

= = Rate this question :

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