Q. 8 E5.0( 1 Vote )

# Find the inverse of each of the following matrices. |A| = = 0 – 1(16 – 12) – 1( – 12 + 9)

= – 4 + 3

= – 1

Hence, A – 1 exists

Cofactors of A are:

C11 = 0 C21 = – 1 C31 = 1

C12 = – 4 C22 = 3 C32 = – 4

C13 = – 3 C23 = 3 C33 = – 4

adj A = = So, adj A = Now, A – 1 = .adj A

So, A – 1 = . Hence, A – 1 = Rate this question :

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