Answer :

|A| =


= 2(4 – 1) + 1( – 2 + 1) + 1(1 – 2)


= 6 – 2


= – 4


Hence, A – 1 exists


Cofactors of A are:


C11 = 3 C21 = 1 C31 = – 1


C12 = + 1 C22 = 3 C32 = 1


C13 = – 1 C23 = 1 C33 = 3


adj A =


=


So, adj A =


Now, A – 1 = .adj A


So, A – 1 = .


Hence, A – 1 =


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