# Find the zeroes of the quadratic polynomial x2 — 6x + 8.

Equating the expression with 0,

x2 — 6x + 8 = 0

On factorising it further,

x2 - 4x - 2x + 8 = 0

x(x - 4) – 2(x - 4) = 0

(x - 4) (x - 2) = 0

x = 4 or x = 2

The zeroes of x2 — 6x + 8 are 4 & 2.

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