# Find the values of y for which the distance between the points P(2, – 3) and Q (10, y) is 10 units.

Given: Distance between (2, - 3) and (10, y) is 10

To find: y

By distance formula, Distance between two points A(x1, y1) and B(x2, y2) is

AB = √((x2 - x1)2 + (y2 - y1)2)

Therefore,

√[(2 - 10)2 + (-3- y)2] = 10

√[(-8)2 + (3+ y)2] = 10

Squaring both sides to remove the square root,

⇒ 64 + (y + 3)2 = 100

⇒  (y + 3)2 = 100 - 64

⇒ (y + 3)2 = 36

⇒ y + 3 = ±6

⇒ (y + 3) will give two values 6 and -6 as answer because both the values when squared will give 36 as answer.)

y + 3 = 6 or y + 3 = -6

Therefore, y = 3 or -9

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos  Section Formula30 mins  Champ Quiz | Previous Year NTSE QuestionsFREE Class  Measuring distance by Distance formula49 mins  Imp. Qs. on Distance Formula68 mins  Champ Quiz | Distance Formula30 mins  Champ Quiz | Coordinate Geometry Problems38 mins  Quiz | Solving Important Questions on Section Formula54 mins  Coordinate Geometry Important Questions38 mins  Important Questions of Coordinate Geometry39 mins  Previous Year RMO Questions43 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses 