Q. 7 D5.0( 1 Vote )

Find the inverse of each of the following matrices:


Answer :

Now, |A| = 2 + 15 = 17


Hence, A – 1 exists.


Cofactors of A are


C11 = 1


C12 = 3


C21 = – 5


C22 = 2


Since, adj A =


(adj A) =


=


Now, A – 1 = .adj A


A – 1 = .


A – 1 = .


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