# Check whether (5, – 2), (6, 4) and (7, – 2) are the vertices of an isosceles triangle Distance between two points A(x1, y1) and B(x2, y2) is given by

D = √(x2 - x1)2 + (y2 - y1)2

Let us assume that points (5, - 2), (6, 4), and (7, - 2) are representing the vertices A, B, and C of the given triangle respectively as shown in the figure.

AB = [(5- 6)2 + (-2- 4)2]1/2

= = BC = [(6- 7)2 + (4 + 2)2]1/2

= = CA = [(5- 7)2 + (-2+ 2)2]1/2

= = 2

Therefore, AB = BC

As two sides are equal in length, therefore, ABC is an isosceles triangle

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos  Section Formula30 mins  Champ Quiz | Previous Year NTSE QuestionsFREE Class  Measuring distance by Distance formula49 mins  Imp. Qs. on Distance Formula68 mins  Champ Quiz | Distance Formula30 mins  Coordinate Geometry Important Questions38 mins  Champ Quiz | Coordinate Geometry Problems38 mins  Quiz | Solving Important Questions on Section Formula54 mins  Important Questions of Coordinate Geometry39 mins  Previous Year RMO Questions43 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses 