Q. 35.0( 1 Vote )

# In ΔPQR, <img wid

Answer : mQ = 90

RM = 12

MP = 8

RP = (RM + MP) = 20

Let QM be x

Applying Pythagoras theorem in ΔQMP, we get

QP2 = x2 + 82 = x2 + 64

Applying Pythagoras theorem in ΔQMR, we get

QR2 = x2 + 122 = x2 + 144

Applying Pythagoras theorem in ΔPQR, we get

RP2 = (x2 + 64) + (x2 + 144)

400 = 208 + 2x2

x2 = 96

x = 4√6

QM = 4√6

PQ2 = x2 + 64

PQ2 = 160

PQ = 4√10

QR2 = x2 + 144

QR2 = 240

QR = 4√15

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