Answer :

cos^{2}θ + sec^{2}θ = 2 + sinθ

Let θ = 0°

LHS = cos^{2}θ + sec^{2}θ = cos^{2}θ° + sec^{2}0° = 1 +1 = 2 … (1)

RHS = 2 + sinθ = 2 + sin0° = 2 + 0 = 2 … (2)

From (1) and (2), LHS = RHS.

∴ The given equation is an identity.

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