# If the distance between the points (4, p) and (1, 0) is 5, then the value of p isA. 4 onlyB. C. – 4 onlyD. 0

Given,

The distance between the points (4, p) and (1, 0) = 5

By using the formula of distance, We get; Distance between the points (x1, y1) and (x2, y2)  On squaring both the sides, we get

9 + p2 = 25

p2 = 16 p = ± 4

Hence, the required value of p is ± 4

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