Q. 125.0( 1 Vote )

# The sides of a t<

Let a2 + b2 = p, 2ab = q, a2 — b2 = r

Since a, b ϵ R + , hence

p is the largest side of the triangle

p2 = (a2 + b2)2 = a4 + b4 + 2a2b2

q2 + r2 = 4a2b2 + (a2 – b2)2

q2 + r2 = a4 + b4 + 2a2b2

So p2 = q2 + r2

Hence the Pythagoras theorem is established

Hence the angle opposite to the side p = a2 + b2 is a right angle

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