Answer :

11.JPG


mQ = 90


Applying Pythagoras theorem


PM2 = QM2 + PQ2


RN2 = QN2 + QR2


Adding the above two equations we get


PM2 + RN2 = QM2 + PQ2 + QN2 + QR2


PM2 + RN2 = (QM2 + QN2) + (PQ2 + QR2)


PM2 + RN2 = MN2 + PR2


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Match the ColumnsMatch the ColumnsMatch the Columns38 mins
Trigo Marathon Part 2Trigo Marathon Part 2Trigo Marathon Part 245 mins
Arithmetic Progression and 'nth' Term of APArithmetic Progression and 'nth' Term of APArithmetic Progression and 'nth' Term of AP55 mins
Trigo Marathon Part 1Trigo Marathon Part 1Trigo Marathon Part 146 mins
Heights and Distances - IIHeights and Distances - IIHeights and Distances - II45 mins
Heights and Distances - IHeights and Distances - IHeights and Distances - I54 mins
Application of Trigo Important QuestionsApplication of Trigo Important QuestionsApplication of Trigo Important Questions44 mins
Chemical Properties of Metal and Non MetalChemical Properties of Metal and Non MetalChemical Properties of Metal and Non Metal61 mins
Extraction of MetalExtraction of MetalExtraction of Metal56 mins
Purification of MetalsPurification of MetalsPurification of Metals60 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

AB = AC and <spanGujarat Board Mathematics

<spGujarat Board Mathematics

In ΔPQR, <img widGujarat Board Mathematics

m<sGujarat Board Mathematics

In ΔABC, mGujarat Board Mathematics

In ΔABC, mGujarat Board Mathematics

In ΔXYZ, mGujarat Board Mathematics

In ΔABC, mGujarat Board Mathematics

In ΔPQR, mGujarat Board Mathematics

â<spGujarat Board Mathematics