Q. 81 F

# Add:3a(a-b-c), 2b (a-b + c)

To find: 3a(a - b - c) + 2b(a - b + c)

Here,
3a(a - b - c) = 3a- 3ab - 3ac

2b(a - b + c) = 2ab - 2b2 + 2bc

Hence the two polynomials to be added are 3a- 3ab - 3ac and 2ab - 2b2 + 2bc

3a(a - b - c) + 2b(a - b + c) = 3a- 3ab - 3ac + 2ab - 2b2 + 2bc = 3a- ab - 3ac + 2bc - 2b2

The result is as follows: 3a- ab - 3ac + 2bc - 2b2

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