Answer :

Let two consecutive numbers be x and (x + 1).

Then square of these numbers are x2 and (x + 1)2.


Difference of squares of these consecutive numbers = (x + 1)2 – x2


= x2 + 1 + 2x – x2 [, (a + b)2 = a2 + b2 + 2ab)


= 2x + 1


= x + x + 1


= (x) + (x + 1)


= sum of the two consecutive numbers x and x+1


Thus, difference of squares of two consecutive numbers = sum of the same consecutive numbers.


Hence, the statement is true.


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Subtract:

NCERT - Mathematics Exemplar

Take away:
</p
RD Sharma - Mathematics

Subtract 3x-4y-7zRD Sharma - Mathematics

Subtract:

RD Sharma - Mathematics

If we subtract -3NCERT - Mathematics Exemplar

Add:

<spanNCERT - Mathematics Exemplar

State whether theNCERT - Mathematics Exemplar

Add:

<sNCERT - Mathematics Exemplar

Subtract:

NCERT - Mathematics Exemplar

Add:

<sNCERT - Mathematics Exemplar