# The number of ways in which we can choose a committee from four men and six women so that the committee includes at least two men and exactly twice as many women as men isA. 94B. 126C. 128D. None

Formula:- (i)nCr=

Given:-

Number of women=6,number of men =4

Group I should of 2 men and 4 women=4C2.6C4

GROUP II should of 3 men and 6 women=4C3.6C6

Required committee=4C2.6C4+4C3.6C6

=90+4

=94

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