Q. 375.0( 2 Votes )

# The number of ways in which we can choose a committee from four men and six women so that the committee includes at least two men and exactly twice as many women as men is

A. 94

B. 126

C. 128

D. None

Answer :

Formula:- (i)^{n}C_{r}=

Given:-

Number of women=6,number of men =4

Group I should of 2 men and 4 women=^{4}C_{2}.^{6}C_{4}

GROUP II should of 3 men and 6 women=^{4}C_{3}.^{6}C_{6}

Required committee=^{4}C_{2}.^{6}C_{4}+^{4}C_{3}.^{6}C_{6}

=90+4

=94

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