# Factorised form of 23xy – 46x + 54y – 108 isA. (23x + 54) (y – 2)B. (23x + 54y) (y – 2)C. (23xy + 54y) (-46x – 108)D. (23x + 54) (y + 2)

lets write factorise form of 23xy – 46x + 54y – 108

23xy – 46x + 54y – 108 = 23x(y – 2) + 54(y – 2)
Taking (y-2) as common from the term, we get,

= (y – 2)(23x + 54)

= (23x + 54)(y – 2)

Hence, option (a) is correct

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