Q. 105.0( 1 Vote )
Solve 
, when x ϵ R.
Answer :
Observe that 
is zero at x = -5 and not defined at x = 5
Hence plotting these two points on number line
Now for x > 5, 
is positive
For every root and not defined value of 
the sign will change
We want greater than zero that is the positive part hence x < -5 and x > 5
x < -5 means x is from negative infinity to -5 and x > 5 means x is from 5 to infinity
Hence x ∈ (-∞, -5) U (5, ∞)
Hence solution of 
is x ∈ (-∞, 2) U (5, ∞)
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