Answer :

-11 ≤ 4x – 3 and 4x – 3 ≤ 13


When,


-11 ≤ 4x - 3


4x – 3 ≥ -11


Adding 3 to both the sides


4x – 3 + 3 ≥ -11 + 3


4x ≥ - 8


Divide both the sides by 4 in above equation



x ≥ -2


Now when,


4x – 3 ≤ 13


Adding 3 to both the sides in the above equation


4x – 3 + 3 ≤ 13 + 3


4x ≤ 16


Dividing both the sides by 4 in the above question



x ≤ 4


Combining the intervals:
x ≥ -2 and x ≤ 4


Therefore,


x ϵ [-2, 4]


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