Answer :

Given:

GF = 50 m

GH = 34 m

HF = 52 m

Semi perimeter of Δ GHF =

According to Heron’s formula

Area of the triangle = √(s(s-a)(s-b)(s-c))

⇒ Area of the triangle Δ GHF = 816 sq m

Given:

HE = 20 m

EF = 48 m

HF = 52 m

Semi perimeter of Δ EHF =

According to Heron’s formula

Area of the triangle = √(s(s-a)(s-b)(s-c))

⇒ Area of the triangle Δ EHF = 480 sq m

Area of EFGH = Area of the triangle Δ GHF + Area of the triangle Δ EHF = 1296 sq m

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