Answer :
Given:
GF = 50 m
GH = 34 m
HF = 52 m
Semi perimeter of Δ GHF =
According to Heron’s formula
Area of the triangle = √(s(s-a)(s-b)(s-c))
⇒ Area of the triangle Δ GHF = 816 sq m
Given:
HE = 20 m
EF = 48 m
HF = 52 m
Semi perimeter of Δ EHF =
According to Heron’s formula
Area of the triangle = √(s(s-a)(s-b)(s-c))
⇒ Area of the triangle Δ EHF = 480 sq m
Area of EFGH = Area of the triangle Δ GHF + Area of the triangle Δ EHF = 1296 sq m
Rate this question :
How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Area of Polygons41 mins
Quiz | Visualising Solid Shapes36 mins
NCERT | Surface Area of Solid Shapes39 mins
Surface Area and Volume of Cube56 mins
Lets Roll Around a Circle51 mins
Smart Revision | Surface Area and Volume of Cylinder48 mins
Smart Revision | Surface Area and Volume of Cuboid50 mins














Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
view all courses
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation


RELATED QUESTIONS :
The area of a par
MHB - Mathematics (Old)The area of a par
MHB - Mathematics (Old)The diagonals of
MHB - Mathematics (Old)The lengths of th
MHB - Mathematics (Old)The area of a rho
MHB - Mathematics (Old)Using the measure
MHB - Mathematics (Old)The <span lang="E
MHB - Mathematics (Old)The area of a rho
MHB - Mathematics (Old)The area of a par
MHB - Mathematics (Old)What is the area
MHB - Mathematics (Old)