Q. 65.0( 1 Vote )

Using the measure

Answer :

Given:


GF = 50 m


GH = 34 m


HF = 52 m


Semi perimeter of Δ GHF =


According to Heron’s formula


Area of the triangle = √(s(s-a)(s-b)(s-c))


Area of the triangle Δ GHF = 816 sq m


Given:


HE = 20 m


EF = 48 m


HF = 52 m


Semi perimeter of Δ EHF =


According to Heron’s formula


Area of the triangle = √(s(s-a)(s-b)(s-c))


Area of the triangle Δ EHF = 480 sq m


Area of EFGH = Area of the triangle Δ GHF + Area of the triangle Δ EHF = 1296 sq m


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