Q. 9 4.1( 53 Votes )

In Fig. 6.63, D is a point on side BC of Δ ABC such thatbd/cd = ab/acProve that AD is the bisector of BAC

Answer :

To Prove : AD bisects ∠BAC

Now from ΔABD and ΔADC,
As it is given that

And, AD is common to both triangles,
ΔABD ∼ ΔADC (BY SSS theorem)
Now by similarity ∠BAD =  ∠DAC
Hence, AD must be the bisector of the angle BAC

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