Q. 7 E5.0( 4 Votes )

The bisector of P in ΔPQR intersects in D. If QD: RD = 4 : 7 and PR = 14, then PQ = ………..
A. 8

B. 4

C. 12

D. 16

Answer :

We have

Given: PD is the bisector of P.

QD:RD = 4:7

PR = 14

To find: PQ = ?

In ∆PQR, the bisector of P intersects the line QR at D. By property of triangles,

PQ = 2 × 4

PQ = 8

Thus, option (a) is correct.

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