Q. 7 C5.0( 2 Votes )

In ΔABC, B—M—C and A—N—C, ||. If NC : NA = 1 : 3 and CM = 4, then BC = ………..
A. 12

B. 16

C. 8

D. 1/2

Answer :

We have the diagram as,



Given: In ∆ABC,


MN AB


NC:NA = 1:3



CM = 4


To find: BC = ?


In ∆ABC,


Since, MN AB




MB = 4 × 3 [, ]


MB = 12


In B – M – C,


BC = MB + CM


BC = 12 + 4


BC = 16


Thus, option (b) is correct.

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