Given: Area of ∆ABC = 36,
Area of ∆PQR = 64
AB = 12
The correspondence ABC ↔ PQR is a similarity.
To find: PQ = ?
Recall the property,
Ratio of areas of two similar triangles = Ratio of squares of the corresponding sides
⇒ PQ = 2 × 8
⇒ PQ = 16
Thus, answer is 16.
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