(i) 4x = 522 - 4824x = (52 – 48) (52 + 48)4x = 4 × 1004x = 400x = 100(ii) 14x = (47 – 33) (47 + 33)14x = 14 × 80x = 80(iii) Using formula:a2 – b2 = (a – b) (a + b), we get5x = (50 – 40) (50 + 40)5x = 10 × 905x = 900x = 180

Q. 64.3( 3 Votes )

Find the value of

Class 8th RD Sharma - Mathematics 6. Algebraic Expressions and Identities

Answer :

(i) 4x = 52² - 48²

4x = (52 – 48) (52 + 48)

4x = 4 × 100

4x = 400

x = 100

(ii)

14x = (47 – 33) (47 + 33)

14x = 14 × 80

x = 80

(iii)

Using formula:

a² – b² = (a – b) (a + b), we get

5x = (50 – 40) (50 + 40)

5x = 10 × 90

5x = 900

x = 180

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