Q. 34.4( 67 Votes )

Answer :

Using Pythagoras theorem in ΔADB, we get:

AB^{2} = AD^{2} + DB^{2} (i)

Applying Pythagoras theorem in ΔACD, we obtain

AC^{2} = AD^{2} + DC^{2}

AC^{2} = AD^{2} + (DB + BC)^{2}

AC^{2} = AD^{2} + DB^{2} + BC^{2} + 2DB x BC

AC^{2} = AB^{2} + BC^{2}+ 2DB x BC [Using equation (i)]

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