Using Pythagoras theorem in ΔADB, we get:AB2 = AD2 + DB2 (i)Applying Pythagoras theorem in ΔACD, we obtainAC2 = AD2 + DC2AC2 = AD2 + (DB + BC)2AC2 = AD2 + DB2 + BC2 + 2DB x BCAC2 = AB2 + BC2+ 2DB x BC [Using equation (i)]

Q. 34.4( 101 Votes )

In Fig. 6.58, ABC

Class 10th NCERT - Mathematics 6. Triangles

Answer :

Using Pythagoras theorem in ΔADB, we get:

AB² = AD² + DB² (i)

Applying Pythagoras theorem in ΔACD, we obtain

AC² = AD² + DC²

AC² = AD² + (DB + BC)²

AC² = AD² + DB² + BC² + 2DB x BC

AC² = AB² + BC²+ 2DB x BC [Using equation (i)]

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