Q. 19

# Simplify:

(i)

(x2 – y2) (x2 + y2) (x4 + y4)

= [(x2)2 – (y2)2] (x4 + y4)

= (x4 – y4) (x4 – y4)

= [(x4)2 – (y4)2]

= x8 – y8

(ii)

[(2x)2 – (1)2] (4x2 + 1) (16x4 + 1)

= (4x2 – 1) (4x2 + 1) (16x4 + 1) 1

= [(4x2)2 – (1)2] (16x4 + 1) 1

= (16x4 – 1) (16x4 + 1) 1

= [(16x4)2 – (1)2] 1

= 256x8 – 1

(iii)

(7m)2 + (8n)2 – 112mn + (7m)2 + (8n)2 + 112mn

= 49m2 + 64n2 + 49m2 + 64n2

= 98m2 + 64n2 + 64n2

= 98m2 + 128n2

(iv)

(2.5p)2 + (1.5q)2 – 2 (2.5p) (1.5q) – (1.5p)2 – (2.5q)2 + 2 (1.5p) (2.5q)

= 6.25p2 + 2.25q2 – 2.25p2 – 6.25q2

= 4p2 – 6.25q2 + 2.25q2

= 4p2 – 4q2

= 4 (p2 – q2)

(v)

(m2)2 – 2 (m2) (n2) (m) + (n2m)2 + 2m3n2

= m4 – 2m3n2 + (n2m)2 + 2m3n2

= m4 + n4m2 – 2m3n2 + 2m3n2

= m4 + m2n4

= m2 (m2 + n4)

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

What must be addeRD Sharma - Mathematics

Fill in the blankNCERT - Mathematics Exemplar

Show that:
</p
RD Sharma - Mathematics