Answer :

Let us assume a rhombus ABCD having diagonals AC and BD


Diagonals of this rhombus ABCD intersects each other at a point O.



We know that,


Diagonals of rhombus bisects each other at 90o


Now,


AO = = = 8 cm


BO = = = 15 cm


By applying Pythagoras theorem, we get:


OA2 + OB2 = AB2


82 + 152 = AB2


64 + 225 = AB2


AB2 = 289


AB =


AB = 17 cm


The length of the side of Rhombus = 17 cm


Perimeter of rhombus = 4 × Side of rhombus


= 4 × 17


= 68 cm

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