# Using factor theo

Let, f (x) = 3x3-x2-3x+1

The factors of the constant term

The factor of the coefficient of x3 is 3. Hence, possible rational roots of f (x) are:

We have,

f (1) = 3 (1)3 – (1)2 – 3 (1) + 1

= 3 – 1 – 3 + 1

= 0

So, (x – 1) is a factor of f (x)

Let us now divide

f (x) = 3x3-x2-3x+1 by (x - 1) to get the other factors of f (x)

Using long division method, we get

3x3-x2-3x+1 = (x – 1) (3x2 + 2x – 1)

Now,

3x2 + 2x - 1 = 3x2 + 3x – x – 1

= 3x (x + 1) – 1 (x + 1)

= (3x – 1) (x + 1)

Hence, 3x3-x2-3x+1 = (x – 1) (x + 1) (3x – 1)

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Division of Polynomials46 mins
Quiz- Test what you Know Part 246 mins
Polynomials- Introduction45 mins
Identities Ke Master Bane47 mins
Quiz- Test what you Know64 mins
Newton's Second Law46 mins
Conservation of Energy41 mins
Pair of Angles29 mins
Newton's Third Law44 mins
Miscellaneous questions42 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

Factorize:
</p
RS Aggarwal & V Aggarwal - Mathematics

Find the vaRS Aggarwal & V Aggarwal - Mathematics

Factorize:
</p
RS Aggarwal & V Aggarwal - Mathematics

Factorize:
</p
RS Aggarwal & V Aggarwal - Mathematics

Factorize:
</p
RS Aggarwal & V Aggarwal - Mathematics

If <span lang="ENNCERT Mathematics Exemplar

Show that p – 1 iNCERT Mathematics Exemplar

Factorize:
</p
RS Aggarwal & V Aggarwal - Mathematics

Find the value ofNCERT Mathematics Exemplar