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In the above question, it is given that:

In PQR, we have

∠Q = 25^o and ∠R = 65^o

We know that,

The sum of interior angles of a triangle = 180^o

∠PQR + ∠PRQ + ∠QPR = 180^o

25^o + 65^o + ∠QPR = 180^o

90^o + ∠QPR = 180^o

∠QPR = 180^o – 90^o

= 90^o

Hence, is right angled at point P

Thus,

By using Pythagoras theorem, we get:

(PR)² + (PQ)² = (QR)²

Hence,

Option (ii) is true