Q. 5 D5.0( 6 Votes )
Find the absolute maximum value and the absolute minimum value of the following functions in the given intervals:
f (x) = (x − 1)2 + 3, x ∈ [−3, 1]
Answer :
It is given that f (x) = (x − 1)2 + 3, x ∈ [−3,1]
⇒ f’(x) = 2(x – 1)
Now, f’(x) = 0
⇒ 2(x-1)
⇒ x = 1
Now, we evaluate the value of f at critical point x = 1 and at end points of the interval [-3, 1].
f(1) = (1 - 1)2 + 3 = 0 + 3 = 3
f(-3) = (-3 - 1)2 + 3 = 16 + 3 = 19
Therefore, we have the absolute maximum value of f on [-3, 1] is 19 occurring at x =-3.
And, the absolute minimum value of f on [-3,1] is 3 occurring at x = 1.
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