Q. 5 D4.1( 15 Votes )

# Find the ab

It is given that f (x) = (x − 1)2 + 3, x [3,1]

f’(x) = 2(x – 1)

Now, f’(x) = 0

2(x-1)

x = 1

Now, we evaluate the value of f at critical point x = 1 and at end points of the interval [-3, 1].

f(1) = (1 - 1)2 + 3 = 0 + 3 = 3

f(-3) = (-3 - 1)2 + 3 = 16 + 3 = 19

Therefore, we have the absolute maximum value of f on [-3, 1] is 19 occurring at x =-3.

And, the absolute minimum value of f on [-3,1] is 3 occurring at x = 1.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

If the sum of theMathematics - Board Papers

A metal box with Mathematics - Board Papers

Show that aRD Sharma - Volume 1

Find the local maMathematics - Board Papers

Prove that the seMathematics - Board Papers

Prove that the raMathematics - Board Papers

Prove that the leMathematics - Board Papers