Q. 5 B4.2( 18 Votes )

# Find the ab

Answer :

It is given that f (x) = sin x + cos x, x [0, π]

f’(x) = cosx - sinx

Now, f’(x) = 0

cosx - sinx = 0

cosx = sinx

tanx = 1

x = Now, we evaluate the value of f at critical point and at end points of the interval [0, π] f(0) = sin0 +cos0 = 0+1 = 1

f(π) = sin π + cos π = 0 -1 = -1

Therefore, we have the absolute maximum value of f on [0, π] is √2 occurring at And, the absolute minimum value of f on [0, π] is -1 occurring at x = π.

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