Answer :

h(x) = sin x + cos x,

h’(x) = cosx - sinx

Now, h’(x) = 0

cosx - sinx = 0

cosx = sinx

tanx = 1

h’’(x) = -sinx – cosx = -(sinx + cosx)

Then, by second derivative test,

is point of local maxima and local minima of h at is

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