Answer :

It is given that h(x) = x + 1, x (1, 1)

Now, if a point x0 is closest to -1, then,


We find for all x0 (1, 1)


Also, if a point x1 is closest to 1, then,


We find for all x1 (1, 1)


Therefore, the function h (x) has neither maximum nor minimum value in (-1, 1).


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