Answer :

It is given that f (x) = |x + 2| – 1

Now, we can see that |x + 2| ≥ 0 for every x ϵ R


f (x) = |x + 2| – 1 ≥ -1 for every x ϵ R


The minimum value of f is attained when |x + 2| = 0


|x + 2| =0


x = -2


Then, Minimum value of f = f(-2) = |-2 + 2| - 1 = -1


Therefore, function f does not have a maximum value.


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