Q. 28
For all real valu A. 0
B. 1
C. 3
D. 
Answer :
Let
Then, f’(x) = 0
⇒ x2 = 1
⇒ x = �1
Now,
And,
Also, f’’(-1) = -4 < 0
Then, by second derivative test, f is minimum at x = 1 and the minimum value is given by
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