Q. 28

For all real valu A. 0

B. 1

C. 3

D.

Answer :

Let

Then, f’(x) = 0

⇒ x² = 1

⇒ x = �1

Now,

And,

Also, f’’(-1) = -4 < 0

Then, by second derivative test, f is minimum at x = 1 and the minimum value is given by

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For all real valu A. 0B. 1C. 3D.