Answer :

We know that total surface area of the cone = S = πr(l + r) …(1)

and Volume of the cone(V) =

Then by (1), we get,

P = V^{2}

Now, differentiating P with respect to r, we get,

Now, if, , then

S = 4πr^{2}

Now again differentiating with respect to r, we get

Therefore, P is maximum when S = 4πr^{2}

And V is maximum when S = 4πr^{2}

⇒ πr(l + r) = 4πr^{2}

⇒ l = 3r

SinƟ =

Therefore, semi-vertical angle of right circular cone of given surface area and maximum volume is .

Hence Proved.

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