Answer :

Let r be the radius and h be the height of the cylinder.

Let V be the volume of the cylinder. Then

V = πr2h = 100(given)

h =

hen, the surface area (S) of the cylinder is given by:

S = 2πr2 + 2πrh

Now, , <0


So, when then > 0

Then, by second derivative test, the surface area is the minimum when

Now, when then h = cm.

Therefore, the dimensions of the can which has the minimum surface area are and h cm.

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