Q. 214.2( 37 Votes )
Of all the closed
Let r be the radius and h be the height of the cylinder.
Let V be the volume of the cylinder. Then
V = πr2h = 100(given)
⇒ h =
hen, the surface area (S) of the cylinder is given by:
S = 2πr2 + 2πrh
Now, , <0
So, when then > 0
Then, by second derivative test, the surface area is the minimum when
Now, when then h = cm.
Therefore, the dimensions of the can which has the minimum surface area are and h cm.
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