Answer :

It is given that f (x) = –(x – 1)2 + 10

Now, we can see that (x - 1)2 ≥ 0 for every x ϵ R


f (x) = –(x – 1)2 + 10 ≤ 10 for every x ϵ R


The minimum value of f is attained when x - 1 = 0


x - 1 = 0


x = 1


Then, Maximum value of f = f(1) = -(1-1)2 + 10 = 10


Therefore, function f does not have a minimum value.


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

If the sum of theMathematics - Board Papers

A metal box with Mathematics - Board Papers

Show that aRD Sharma - Volume 1

Find the local maMathematics - Board Papers

Prove that the seMathematics - Board Papers

Prove that the raMathematics - Board Papers

Prove that the leMathematics - Board Papers