Q. 1 C

f(x) = – (x – 1)

Answer :

It is given that f (x) = –(x – 1)^{2} + 10

Now, we can see that (x - 1)^{2} ≥ 0 for every x ϵ R

⇒ f (x) = –(x – 1)^{2} + 10 ≤ 10 for every x ϵ R

The minimum value of f is attained when x - 1 = 0

x - 1 = 0

⇒ x = 1

Then, Maximum value of f = f(1) = -(1-1)^{2} + 10 = 10

Therefore, function f does not have a minimum value.

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