Using factor theo

Let, f (x) = x³+13x²+32x+20

The factors of the constant term + 20 are

Putting x = -1, we have

f (-1) = (-1)³ + 13 (-1)² + 32 (-1) + 20

= -1 + 13 – 32 + 20

= 0

So, (x + 1) is a factor of f (x)

Let us now divide

f (x) = x³+13x²+32x+20 by (x + 1) to get the other factors of f (x)

Using long division method, we get

x³+13x²+32x+20 = (x + 1) (x² + 12x + 20)

x² + 2x + 20 = x² + 10x + 2x + 20

= x (x + 10) + 2 (x + 10)

= (x + 10) (x + 2)

Hence, x³+13x²+32x+20 = (x + 1) (x + 10) (x + 2)